How to Determine the Parachor value of the given liquid?
Experiment:
Determine the Parachor value of the given liquid. Molecular weight of the given liquid is 32.
Theory:
Macleod
in 1923 discovered a relationship between surface tension and density for
normal liquids. It is expressed as
C = g1/4 / D – d
Where
g is
the surface tension of the liquid, D is density of the liquid, d is the density
of vapour and C is a constant, characteristic of the liquid. This equation
holds well over a wide range of temperature. In 1924, it was pointed out by Sudgen
that the following expression is also valid.
MC =
Mg1/4 / D – d
Where
M is the molar mass (molecular weight). MC was called Parachor, denoted by [P].
Mg1/4 / D – d = [P]
At
ordinary temperature d is negligible, therefore
[P]
= Mg1/4/D
Apparatus:
Stalagmometer,
specific gravity bottle, screw type pinch cock, beakers, rubber tube, balance,
stand etc.
Procedure:
·
Take
a stalagmometer, wash it with ether, dry it and then fill it with water up to
the level of the upper mark A by sucking through rubber tube.
·
Release
water at a very slow rate and count the number of drops of water from the upper
mark A to the lower mark B.
·
Also
count the number of drops for each of the given liquids in the same way.
·
Take
a specific gravity bottle and weigh it. Then fill it with water and weight it.
·
Find
the weight of water by subtracting the weight of empty bottle from the total
weight of bottle filled with water.
·
Also
find the weight of each liquid in the same way. Then calculate the density of
each of the liquid as follows.
Density
of Liquid = (Weight of liquid / Weight of water) x Density of water as density
of water is usually taken as 1 therefore Density of liquid = (Weight of liquid
/ Weight of water)
Observations:
Liquid |
No. of Drops (n) |
Surface tension (g) |
Water |
|
|
Given
Liquid |
|
|
Room
temperature = oC
Weight
of empty specific gravity bottle =W1 g
Weight
of empty specific gravity bottle + water = W2 g
Weight
of water = W2 – W1 = W3
Weight
of specific gravity bottle + liquid 1 = W4 g
Weight
of liquid =W4 – W1 = W5 g
Calculations:
Surface
tension of a liquid is calculated using the following relationship
gl = gwx (nw
/ nl) x (dl/ dw)
Surface
tension of water at 30oC is 71.22
Molar
mass of the liquid =
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